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ν”„λ‘œκ·Έλž˜λ¨ΈμŠ€ 1단계 : μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜?

by μ½”νŒŒμΉ΄ 2022. 11. 1.
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ν”„λ‘œκ·Έλž˜λ¨ΈμŠ€ 1단계 : μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜?

μ½”λ”©ν…ŒμŠ€νŠΈ μ—°μŠ΅ > μ—°μŠ΅λ¬Έμ œ > μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜?


πŸ’© 문제 μ„€λͺ…

길이가 n이고, "μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜...."와 같은 νŒ¨ν„΄μ„ μœ μ§€ν•˜λŠ” λ¬Έμžμ—΄μ„ λ¦¬ν„΄ν•˜λŠ” ν•¨μˆ˜, solution을 μ™„μ„±ν•˜μ„Έμš”. 예λ₯Όλ“€μ–΄ n이 4이면 "μˆ˜λ°•μˆ˜λ°•"을 λ¦¬ν„΄ν•˜κ³  3이라면 "μˆ˜λ°•μˆ˜"λ₯Ό λ¦¬ν„΄ν•˜λ©΄ λ©λ‹ˆλ‹€.

πŸ’© μ œν•œ 쑰건

☝️ n은 길이 10,000μ΄ν•˜μΈ μžμ—°μˆ˜μž…λ‹ˆλ‹€.

πŸ’© 문제 풀이

function solution(n) {
    var answer = '';
    for(i=1; i<=n; i++){
        (i % 2 == 1) ? answer += "수" : answer += "λ°•";
    }
    return answer;
}

ν™€μˆ˜μΌ 경우 "수", 짝수일 경우 "λ°•"을, n번 좜λ ₯ν•˜λ„λ‘ μ‚Όν•­μ—°μ‚°μžλ₯Ό μ΄μš©ν•΄ μž‘μ—…ν•΄ μ£Όμ—ˆμŠ΅λ‹ˆλ‹€.

πŸ’© λ‹€λ₯Έ 풀이

const waterMelon = n => {
    return 'μˆ˜λ°•'.repeat(n/2) + (n%2 === 1 ? '수' : '');
}

"μˆ˜λ°•" λ¬Έμžμ—΄μ„ n/2번만큼 λ°˜λ³΅μ‹œν‚€κ³ , n이 ν™€μˆ˜μΌ 경우 "수"둜 λλ‚˜λ„λ‘, 짝수일 경우 "λ°•"으둜 λλ‚˜λ„λ‘ μ‚Όν•­μ—°μ‚°μžλ₯Ό μ΄μš©ν•΄ μž‘μ—…ν•œ ν˜•νƒœμž…λ‹ˆλ‹€.

function waterMelon(n){
    var result = "μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•";
    return result.substring(0,n);
}

κ·€μ—¬μš΄ 풀이가 μžˆμ–΄μ„œ κ°€μ Έμ™€λ΄€μŠ΅λ‹ˆλ‹€. μž”λ¨Έλ¦¬κ°€ μˆ˜μ€€κΈ‰μ΄λ„€μš”.

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